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# Super hot tension | Forces and Newton’s laws of motion | Physics | Khan Academy

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22 Replies to “Super hot tension | Forces and Newton’s laws of motion | Physics | Khan Academy”

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High Blood Pressure Information

I clicked on this video because I thought it was about rope bondage. Hurry up with that video please.

David, I followed your steps, but am confused about the results not equaling 30N…

15N + 15 root3 N = 30N ?

Where am I mistaken? (Also, sorry that I don't know how to type "root3" in proper symbols.)

Thank you for these generous and skillful lessons!

I honestly had to look up David in google just to see who he is because of how good a teacher I think he is, thanks again for the clear explanation of the subject!!!

This was… Amazing

that was beautiful

i kinda have an easer way.

wow, but when i did it i just did T1=sin(60)x3 and T2=sin(30)x 3 and i compared my answer and i was off by a factor of 10.

I want some hot peppers now

Isn't it the net force that is equal to zero, rather than a=0? I would have done mg=T1 + T2.

so is super hot tension an actual physics terms or it is just something you made up in order to make this lesson sounds more attractive?

u r awesome man

Why can't you just do T1=30sin(30) and T2=30Sin(60)?

Whoa you can actually do that? Multiply a denominator to a side of the equations that's zero to remove it?

I love this guy idk y tho

That great. Thanks you for this video

i would definitely give a million likes if i could

T2 is wrong it should be 30/sin(60)=34N

When you needed to get everything in terms of 2 variables, why canâ€™t you express the y components in terms of the x components multiplied by tangent of angles? That way, everything is in terms t1x and t2x, but we know that theyâ€™re equal, so we have two equations and one variable, which should be easier.

brilliant!

i hate this more than anything

David David David,you are the definition of a hella cool teacher

now tell me the acceleration of the can and in which direction